Two balls A and B are thrown with speeds u and u/2, respectively. Both the balls cover the same horizontal distance before returning to the plane of projection. If theangle of projection of ball ,B is 15o with the horizontal, then the angle of Projection of A is
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a
sin−118
b
12sin−118
c
13sin−118
d
14sin−118
answer is B.
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Detailed Solution
u2sin2θg=(u/2)2sin30∘g=u28g∴ sin2θ=18 or θ=12sin−118