Two balls of the same mass are shot upwards one after another at an interval of 2 seconds, along the same vertical line with the same initial velocity of 39.2 m/s. They will collide at a height :

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78.4 m.

44.1 m.

73.5 m.

58.5 m.

answer is C.

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Detailed Solution

When they collide displacement will be same but time of travel is t and t - 2.h=Ut−12gt2=U(t−2)−12g(t−2)2Solving t = 5 sec.Substituting h = 73.5 m.

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