Two bar magnets of the same mass, length and breadth but magnetic moments M and 2M, respectively, when placed in same position. have time period of 3 s. What will be the time period when they are placed in opposite position?

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3 s

33 s

3 s

6 s

answer is B.

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Detailed Solution

In sum position, T∝1M1+M2 and in difference position T∝1M1-M2⇒32T2=2M-M2M+M⇒T2=9 x 3∴T=33 s

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