Q.
Two bars are unstressed and have lengths of 25cm and 30cm at 20° as shown in Figure. Bar (1) is of aluminium and bar (2) is of steel. The cross-sectional area of bars are 20cm2 for aluminium and 10cm2 for steel. Assuming that the top and bottom supports are rigid, stress in Al and steel bars in Nmm2 when the temperature is 700C. (Nearly ) Ya=0.70×105N/mm2⋅Ys=2.1×105N/mm2αa=24×10−6/∘C and αs=12.×10−6/∘C
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a
75, 150
b
25, 50
c
50, 100
d
100, 200
answer is A.
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Detailed Solution
Contraction of the two bars due to compressive stress = Elongation of the two bars due to rise of temperature SlYAl+SlYSt=(αAlLAlΔt)Al+(αStLsΔt)StForce in steel = force in aluminiumSAl×AAl=SSt×ASt
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