Q.

Two bars are unstressed and have lengths of 25cm and 30cm at 20° as shown in Figure. Bar (1) is of aluminium and bar (2) is of steel. The cross-sectional area of bars are 20cm2 for aluminium and 10cm2 for steel. Assuming that the top and bottom supports are rigid, stress in Al and steel bars in Nmm2 when the temperature is 700C. (Nearly ) Ya=0.70×105N/mm2⋅Ys=2.1×105N/mm2αa=24×10−6/∘C and αs=12.×10−6/∘C

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

75, 150

b

25, 50

c

50, 100

d

100, 200

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Contraction of the two bars due to compressive stress = Elongation of the two bars due to rise of temperature SlYAl+SlYSt=(αAlLAlΔt)Al+(αStLsΔt)StForce in steel = force in aluminiumSAl×AAl=SSt×ASt
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon