Two batteries of emf E1 and E2 (E2 > E1) and internal resistances r1 and r2, respectively are connected in parallel as shown in the figure. Which of the following options is correct ?
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a
The equivalent emf E is smaller than E1.
b
The equivalent emf E = E1 + E2.
c
The equivalent emf E is greater than E2.
d
The equivalent emf Eeq of two cells is between E1 and E2 always.
answer is D.
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Detailed Solution
The equivalent internal resistance of two cells between A and B, Req=r1r2r1+r2 (Parallel combination case of resistances)If E is the equivalent emf of the two cells in parallel between A and B, thenEeq Rv0=E1r1+E2r2=E1r2+E2r1r1r2∴Eeq=E1r2+E2r1r1r2Req=E1r2+E2r1r1+r2 As, E2>E1⇒E1