Two bikes A and B start from a point. A moves with uniform speed 40 m/s and B starts from rest with uniform acceleration 2 m/s2 . lf B starts at t =10 and A starts from the same point at t = 10 s, then the time during the journey in which A was ahead of B is
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a
20 s
b
8 s
c
10 s
d
A is never ahead of B
answer is D.
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Detailed Solution
A will be ahead of B when xA≥xB40(t−10)≥(0)t+12(2)t2 as A is 10sec late than B. ⇒ t2−40t+400≤0⇒ (t−20)2≤0which is not possible, so A will never be ahead at B.