Two blocks A and B each of equal masses m are released from the top of a smooth fixed wedge as shown in the figure. Find the magnitude of the acceleration of the centre of mass of the two blocks (in m/s2). Take g = 10 m/s2
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answer is 5.
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Detailed Solution
Let us consider incline surfaces of wedge as x-axis and y-axis respectively. We can write accelerations of blocks A and B.a→A=g sin 30 i^ and a→B=g sin 60∘ j^The acceleration of centre of mass of two blocks can be written asa→cm=mAa→A+mBa→BmA+mB=mg sin 30∘i^+mg sin 60∘j^m+m=g sin 30∘i^+g sin 60∘j^2=g4i^+3g4j^ ⇒a→cm=g2=5 m/s2