Two blocks of equal mass are tied with a light string which passes over a massless pulley as shown in figure. The magnitude of acceleration of centre of mass of both the blocks is (neglect$$ friction every $$where):

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Infinity Learn · Accepted Answer

mg $$sin$$ $$600-T$$ $$=$$ ma, $$T-mg$$ $$sin$$ $$300$$ $$=$$ maSolving them, we get a $$=$$ $$g(3-1)4a1$$→  $$=$$ $$-acos600i^-asin600j^$$ $$=$$ $$-a2i^-a32j^a2$$→  $$=$$ $$-a$$ $$cos$$ $$300i^$$ $$+$$ a $$cos$$ $$300j^$$ $$=$$ $$-a32i^+a2j^Nowacm$$→ $$=$$ $$m1a1$$→$$+m2a2$$→$$m1+m2$$ $$=$$ $$-ma2(1+3)i^+ma2(1-3)j^2m$$          $$=$$ $$a4$$[$$(1+3)i^+(1-3)j^$$]|acm→| $$=$$ $$a4$$[$$(1+3)2+(1-3)2$$] $$=$$ $$a2$$ $$=g(3-1)42$$

Two blocks of equal mass are tied with a light string which passes over a massless pulley as shown in figure. The magnitude of acceleration of centre of mass of both the blocks is (neglect friction every where):

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