First slide

Motion of centre of mass

Question

Two blocks (from very far apart) are approaching towards each other with velocities as shown in figure. The coefficient of friction for the blocks is µ = 0.2. Initial velocity of centre of mass of the system is

Easy

A

5 ms^-1
B

10 ms^-1
C

15 ms^-1
D

20 ms^-1

Solution

$\large {v_c} = \frac{{{m_1}{v_1} + {m_2}{v_2}}}{{{m_1} + {m_2}}} = \frac{{1 \times 20 + 1 \times ( - 10)}}{{1 + 1}} = 5m/s$

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