First slide

Connected bodies

Question

Two blocks of 2 kg and 1 kg are in contact on a frictionless table. If a force of 3 N is applied on 2 kg block, then the force of contact between the two blocks will be

Easy

A

0 N
B

1 N
C

2 N
D

3 N

Solution

$a = \frac{3}{2 + 1} = 1 {ms}^{- 2} F_{conses} = 1 \times a = 1 \times 1 = 1 N$

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