First slide

Friction on inclined plane of angle more than angle of repose

Question

Two blocks, 4 kg and 2 kg are sliding down an incline plane as shown in Figure. The acceleration of 2 kg block is:

Easy

A

1.66 m/s²
B

2.66 m/s²
C

3.66 m/s²
D

4.66 m/s²

Solution

Both blocks move together so,
$a = \frac{(4 + 2) gsin 30^{\circ} - 0 .3 (4 gcos 30^{\circ}) - 0 .2 (2 gcos 30^{\circ})}{4 + 2}$
= 2.66 m/s²

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