Two blocks of mass $$2$$ kg are connected by a massless ideal spring of spring constant k $$=$$ $$10$$ $$N/m$$. The upper block is suspended from roof by a light string A. The system shown is in equilibrium. The string A is now cut, the acceleration of upper block just after the string A is cut will be $$g=10m/s2$$

Question

Two blocks of mass $$2$$ kg are connected by a massless ideal spring of spring constant k $$=$$ $$10$$ $$N/m$$. The upper block is suspended from roof by a light string A. The system shown is in equilibrium. The string A is now cut, the acceleration of upper block just after the string A is cut will be $$g=10m/s2$$

Infinity Learn · Accepted Answer

Before the string A is cut, let x be elongation in the spring.As system is in equilibrium. $$(see$$ Figure $$(a))Then$$ for lower block,$$kx$$$$=mg=20NJust$$ after the string A is cut $$(see$$ Figure $$(b))For$$ upper block,$$ma=$$$$kx$$$$+mg2a=20+20a=20m/s2$$

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Two blocks of mass 2 kg are connected by a massless ideal spring of spring constant k = 10 N/m. The upper block is suspended from roof by a light string A. The system shown is in equilibrium. The string A is now cut, the acceleration of upper block just after the string A is cut will be g=10m/s2

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material