Two blocks of mass 2 kg are connected by a massless ideal spring of spring constant k = 10 N/m. The upper block is suspended from roof by a light string A. The system shown is in equilibrium. The string A is now cut, the acceleration of upper block just after the string A is cut will be g=10m/s2
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a
0m/s2
b
10m/s2
c
15m/s2
d
20m/s2
answer is D.
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Detailed Solution
Before the string A is cut, let x be elongation in the spring.As system is in equilibrium. (see Figure (a))Then for lower block,kx=mg=20NJust after the string A is cut (see Figure (b))For upper block,ma=kx+mg2a=20+20a=20m/s2