Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Two blocks of mass m1 = 6 kg and m2 = 3 kg are as shown in the diagram. Coefficient of friction between m1 and m2 and between m1 and the surface is 0.5 and 0.4, respectively. The maximum horizontal force that can be applied to the mass m1 so that they move without separation is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

41 N

b

61 N

c

81 N

d

101 N

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

If the blocks move together without any relative motion between them, then their acceleration is given bya=F−0.4(3+6)×10(3+6)m/s2=F−369m/s2Pseudo force on 3 kg block =3a=F−363NThe 3 kg block will not slip on 6 kg block  i.e., If =3a=F−363≤0.5×3×10 ⇒Fmax=81 N
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring