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Q.

Two blocks of mass m1 = 6 kg and m2 = 3 kg are as shown in the diagram. Coefficient of friction between m1 and m2 and between m1 and the surface is 0.5 and 0.4, respectively. The maximum horizontal force that can be applied to the mass m1 so that they move without separation is

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a

41 N

b

61 N

c

81 N

d

101 N

answer is C.

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Detailed Solution

If the blocks move together without any relative motion between them, then their acceleration is given bya=F−0.4(3+6)×10(3+6)m/s2=F−369m/s2Pseudo force on 3 kg block =3a=F−363NThe 3 kg block will not slip on 6 kg block  i.e., If =3a=F−363≤0.5×3×10 ⇒Fmax=81 N
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