First slide

Connected bodies

Question

Two blocks of masses 2 kg and I kg are in contact with each other on a frictionless table. When a horizontal force of 3.0 N is applied to the block of mass 2 kg, the value of the force of contact between the. two blocks is:

Easy

A

4N
B

3N
C

2N
D

1N

Solution

$a = \frac{3}{1 + 2} = 1 m / s^{2}$
Force of contact between blocks = m_Aa = (1) (1) = 1N

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