First slide

Motion of centre of mass

Question

Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a friction less horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of lighter block. The velocity of center of mass is

Moderate

A

30 m/s
B

20 m/s
C

10 m/s
D

5 m/s

Solution

see fig 4
The velocity of center of mass $^{V_{CM}}$ given by the expression

$v_{C M} = \frac{m_{1} v_{1} + m_{2} v_{2}}{m_{1} + m_{2}} S u b s t i t u t i n g t h e g i v e n v a l u e s, w e g e t V_{C M} = \frac{10 \times 14 + 4 \times 0}{10 + 4} = 10 m / s$

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