Questions
Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a friction less horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of lighter block. The velocity of center of mass is
Unlock the full solution & master the concept.
Ready to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is C
see fig 4 The velocity of center of mass VCM given by the expression vCM=m1v1+m2v2m1+m2 Substituting the given values, we get VCM=10×14+4×010+4=10m/sSimilar Questions
A body A of mass M while falling vertically downwards under gravity breaks into two parts; a body B of mass M/3 and body C of mass 2 M/3. The center of mass of bodies B and C taken together shifts compared to that of body A towards
Get your all doubts cleared from
Sri Chaitanya experts
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
