First slide

Motion of centre of mass

Question

Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse give a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of center of mass is

Easy

A

30 m/s
B

20 m/s
C

10 m/s
D

5 m/s

Solution

$\begin{array}{l} v_{com} = \frac{m_{1} v_{1} + m_{2} v_{2}}{m_{1} + m_{2}} = \frac{10 \times 14 + 4 \times 0}{10 + 4} m / s \\ \Rightarrow v_{com} = 10 m / s \end{array}$

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