First slide

Work done by Diff type of forces

Question

Two blocks of masses 2 kg an 4 kg are connected to the free ends of a spring of force constant 800N/m. The blocks are pulled apart so that the spring is stretched by a length ‘x’m. and are released simultaneously, When the spring acquires its natural length, velocity of 2 kg block is 4m/s. Then $ϕ$ elastic potential energy stored in the spring just after the blocks are released is (the surface is smooth)

Moderate

A

32 J
B

24J
C

48 J
D

64 J

Solution

Conserving linear momentum, $4 \times v = 2 \times 4 \Rightarrow v = 2 m / s$
Elastic potential energy stored in the spring
Total kinetic energy of the blocks $\begin{array}{l} = (\frac{1}{2} \times 2 \times 4^{2} \times \frac{1}{2} \times 4 \times 2^{2}) J \\ = 24 J \end{array}$

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