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Two blocks of masses 2 kg an 4 kg are connected to the free ends of a spring of force constant 800N/m. The blocks are pulled apart so that the spring is stretched by a length ‘x’m. and are released simultaneously, When the spring acquires its natural length, velocity of 2 kg block is 4m/s. Then ϕ elastic potential energy stored in the spring just after the blocks are released is (the surface is smooth)

a
32 J
b
24J
c
48 J
d
64 J

detailed solution

Correct option is B

Conserving linear momentum,  4×v=2×4 ⇒v=2m/s    Elastic potential energy stored in the springTotal kinetic energy of the blocks =12×2×42×12×4×22J=24J

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Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


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