Two blocks of masses 2 kg an 4 kg are connected to the free ends of a spring of force constant 800N/m. The blocks are pulled apart so that the spring is stretched by a length ‘x’m. and are released simultaneously, When the spring acquires its natural length, velocity of 2 kg block is 4m/s. Then ϕ elastic potential energy stored in the spring just after the blocks are released is (the surface is smooth)
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a
32 J
b
24J
c
48 J
d
64 J
answer is B.
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Detailed Solution
Conserving linear momentum, 4×v=2×4 ⇒v=2m/s Elastic potential energy stored in the springTotal kinetic energy of the blocks =12×2×42×12×4×22J=24J