Question

Two blocks of masses 10kg and 30 kg are placed along a vertical line if the first block is raised through a height of 7cm then the distance through the second mass should be moved to raise the centre of mass of the system by 1cm is

Moderate

Solution

${Δy}_{cm} = \frac{m_{1} {Δy}_{1} + m_{2} {Δy}_{2}}{m_{1} + m_{2}}$ $\Rightarrow {Δy}_{2} = \frac{(m_{1} + m_{2}) ∆ y_{cm} - m_{1} ∆ y_{1}}{m_{2}} = \frac{40 \times 1 - 10 \times 7}{30} = - 1$ cm

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