Two blocks of masses ‘3m’ and ‘2m’ are in contact on a smooth table. A force P is first applied horizontally on block of mass ‘3m’ and then on mass ‘2m’. The contact forces between the two blocks in the two cases are in the ratio
Acceleration of the system in both cases is given by a = p/5m
N1 = 2m x p/5m ⇒ 2p/5
N2 = 3ma = 3m x p/5m ⇒ 3p/5
N1 : N2 = 2 : 3