Two blocks of masses ‘3m’ and ‘2m’ are in contact on a smooth table. A force P is first applied horizontally on block of mass ‘3m’ and then on mass ‘2m’. The contact forces between the two blocks in the two cases are in the ratio
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a
1:2
b
2:3
c
3:2
d
5:3
answer is B.
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Detailed Solution
Acceleration of the system in both cases is given by a = p/5mN1 = 2m x p/5m ⇒ 2p/5N2 = 3ma = 3m x p/5m ⇒ 3p/5 N1 : N2 = 2 : 3