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Q.

Two blocks of masses m1 and m2 are connected as shown in the figure. The acceleration of the block m2, is:

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a

m2gm1+m2

b

m1gm1+m2

c

4m2g-m1gm1+m2

d

m2gm1+4m2

answer is .

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Detailed Solution

Let a = accn of m1; accn of pulley = a+02 = a2If acceleration of m2 = bThen 0+b2 = a2Hence a = b    T = m1a, m2g -T = m2a∴   a = m2gm1+m2
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