Two blocks of masses M1 and M2, are connected with a string passing over a pulley as shown in figure. The block M1 lies on a horizontal surface. The coefficient of friction between the block M1 and the horizontal surface is μ. The system accelerates. What additional mass m should be placed on the block M1 so that the system does not accelerate?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
M2-M1μ
b
M2μ- M1
c
M2 - M1μ
d
(M2-M1)μ
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
For the equilibrium of block of mass M1:Friction force, f = tension in the string Twhere T = f = μ(m+M1)gt----------(i)For the equilibrium of block of mass M2:T = M2g------------(ii)From (i) and (ii) μ(m+M1)g = M3gm = M2μ-M1
Two blocks of masses M1 and M2, are connected with a string passing over a pulley as shown in figure. The block M1 lies on a horizontal surface. The coefficient of friction between the block M1 and the horizontal surface is μ. The system accelerates. What additional mass m should be placed on the block M1 so that the system does not accelerate?