Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 g and its density is 9 g / cm3. If the mass of the other is 48 g, its density in g / cm3 is

Apparent weight  =V(ρ−σ)g=mρ(ρ−σ)gwhere  m =  mass of the body, ρ=  density of the body  σ=  density of water If two bodies are in equilibrium then their apparent weight must be equal.m1ρ1(ρ1−σ)=m2ρ2(ρ2−σ)    ⇒369(9−1)=48ρ2ρ2−1  By solving we get  ρ2=3.