Two bodies are in equilibrium when suspended in water from the arms at a balance. The mass of one body is 30 g and its density is 6 g/cc. If the mass of the other body is 40g. Find its density ‘d’.

Given Mass of one body m1=30 g Density of body ρ1=6 g/cc Mass of another body m2=40 g Densityρ2=? Apparent weight of 1st body m1g−Fb =(30−306) g  (∵Fb=buoyant force)  (∵Fb=mg) (∵m=ρv∵v=mρ) Apparent weight of 2nd bodym2g−Fb(40−40ρ2×1) g Bodies are in equilibrium So, Apparent weights are equal(30−306)g=(40−40d)g 25=40−40ρ2 ⇒40ρ2=40−25 ⇒ρ2=4015=2.66 g/cc