Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 gand its density is 9 g /cm3 . If the mass of the other is 48g, its density in g/cm3is

Apparent weight = V (ρ-σ)g = mρ(ρ-σ)gwhere m = mass of the body,          ρ = density of the body            σ = density of waterIf two bodies are in equilibrium then their apparent weight must be equal.∴ m1ρ1(ρ1-σ) = m2ρ2(ρ2-σ)⇒ 369(9-1) = 48ρ2(ρ2-1)By solving we get ρ2 = 3