Questions
Two bodies are projected from the same point with equal speeds in such directions that they both strikes the same point on a plane whose inclination is If a be the angle of projection of the first body with the horizontal, the ratio of their times of flight is
detailed solution
Correct option is D
See fig. (3) Let α be the angle of projection of the second body. The range of both the bodies will be the same. Therefore, R=u2gcos2β[sin(2α−β)−sinβ] or sin(2α−β)=sin2α′−β or 2α′−β=π=(2α−β) Now, T=2usin(α−β)gcosβ and T′=2usinα′−βgcosβ∴ TT′=sin(α−β)sinα′−β=sin(α−β)sinπ2−(α−β)−β=sin(α−β)sinπ2−α=sin(α−β)cosαTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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