Two bodies are projected from the same point with equal speeds in such directions that they both strike the same point on a plane whose inclination is β. If α be the angle of projection of the first body with the horizontal the ratio of their times of flight is:
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a
cos(α−β)sinα
b
cosαsin(α−β)
c
sin(α−β)cosα
d
cosαsinα
answer is C.
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Detailed Solution
.Let α' be the angle of projection of the second body range=R=u2g cosβsin(2α−β)−sinβ sin(2α−β)=sin(2α'−β) or 2α'−β=π−(2α−β) ⇒α'=π2−α−βtime of flight=T=2usin(α−β)gcosβ and T1=2usin(α1−β)gcosβ divide the two equations TT1=sin(α−β)sin(α1−β) TT1=sin(α−β)sinπ2−(α−β)−β TT1=sin(α−β)sinπ2−α TT1=sin(α−β)cos α