Two bodies of different masses are dropped simultaneously from same height. If air friction acting on them is directly proportional to the square of their mass, then ,
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a
lighter body reaches the ground earlier
b
heavier body reaches the ground earlier
c
both reach the ground at the same time
d
any of the above
answer is A.
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Detailed Solution
f = k.m2 where k = constant..: a = mg-f/m = (g-km)Again , t = √(2h/a)Therefore , If 'm' increases , 'a' decreases and 't' increases.
Two bodies of different masses are dropped simultaneously from same height. If air friction acting on them is directly proportional to the square of their mass, then ,