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Q.

Two bodies of mass 1 kg and 3 kg have position vectors i^+2j^+k^ and -3i^-2j^+k^, respectively. The centre of mass of this system has a position vector.

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Detailed Solution

The position vector of centre of mass r→ = r→ = m1r1→+m2r2→m1+m2 = 1(i^+2j^+k^ )+3(-3i^-2j^+k^)1+3 = 14(-8i^-4j^+4k^) = -2i^-j^+k^

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