Questions
Two bodies of mass m and M are placed a distance d apart. The gravitational potential at the position where the gravitational field due to them is zero is V. Then :
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Correct option is D
dist from m where field is zero is x which satisfy the condition Gmx2=GMd-x2 solving for x we get x=dmm+M and (d-x) is dMm+M then potential there V=-Gmx-GMd-xsubstituting the values we get VSimilar Questions
When a capillary tube is dipped in water, water rises upto 8 cm in the tube. What happens when the tube is pushed down such that its end is only 5 cm above the outside water level
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