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Q.

Two bodies of masses 1Kg and 2Kg are connected by a steel wire of 2cm2  cross selection. Its running over a smooth a pulley fixed to a rigid support. If g=10ms−2  and Y=2×1011pa , the longitudinal strain in the wire is

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a

3.3×10−7

b

3.3×10−6

c

2×10−6

d

4×10−6

answer is A.

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Detailed Solution

Tension in string is T=2m1m2m1+m2g = 403N Stress in wire S=TA = 203×104pa Strain caused in the wire = stressY=3.3×10−7
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