Question

Two bodies of masses 10 kg and 20 kg are located in x-y plane at (0, 1) and (1, 0). The position of their centre of mass is ………

Easy

Solution

x_cm = $\frac{10 x 0 + 20 x 1}{10 + 20} = \frac{2}{3}$
y_cm= $\frac{10 x 1 + 20 x 0}{10 + 20} = \frac{1}{3}$

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