Questions

Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. Their relative velocity of approach at a separation distance r between them is

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2Gm1+m2r1/2

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r2Gm1m21/2

2Grm1m21/2

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detailed solution

Correct option is A

If v be the relative velocity of approach , then we can write , μvdvdr = -Gm1m2r where μ = m1m2m1+m2= Reduced mass. ⇒∫0vv dv = -G(m1+m2)∫∞r1rdr ⇒v=2G(m1+m2)r Hence the correct choice is (1).

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