Question

Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear momentums is

Easy

Solution

$p = \sqrt{2 mE} ∴ P \propto \sqrt{m} \Rightarrow \frac{P_{1}}{P_{2}} = \sqrt{\frac{m_{1}}{m_{2}}} = \sqrt{\frac{m}{4 m}} = \frac{1}{2}$

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