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Two bodies of masses M1 and M2 are placed at a distance R apart. Then at the position where the gravitational field due to them is zero, the gravitational potential is

a
−GM1R
b
−GM2R
c
−M1+M22GR
d
−M1−M22GR

detailed solution

Correct option is C

GM1x2=GM2(R−x)2 or M2M1x2=R2+x2−2RxLet M2M=kx2(k−1)+2Rx−R2=0x=−2R+4R2+4(k−1)R22(k−1)=RM1M1+M2R−x=RM2M1+M2Gravitational potential at point P is−GM1x+GM2R−x=−GM1M1+M2RM1+GM2M1+M2RM2=−GM2+M1RM1+M2=−GM1+M22R

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