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Two bodies with moment of inertia $I_{1} and I_{2} (I_{1} > I_{2})$ have equal angular momenta. If their kinetic energy of rotation are $E_{1} and E_{2} respectively, then$

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E1 = E2

E1 < E2

E1 > E2

E1≥E2

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detailed solution

Correct option is B

KE = L22l ⇒ KE inversely proportional to I for same L.

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Two bodies with moment of inertia I1 and I2 (I1 > I2) have equal angular momenta. If their kinetic energy of rotation are E1 and E2 respectively, then

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Two bodies with moment of inertia $I_{1} and I_{2} (I_{1} > I_{2})$ have equal angular momenta. If their kinetic energy of rotation are $E_{1} and E_{2} respectively, then$