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Two bodies with moments of inertia $I_{1} and I_{2} (I_{1} > I_{2})$ have equal angular momenta. If their kinetic energies of rotation are E₁ and E₂, respectively, then

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E1=E2

E1>E2

E1≥E2

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detailed solution

Correct option is B

E1=12I1ω12=12I1ω1ω1=12kω1 Now I1ω1=I2ω2=k (say) E2=12I2ω22=12I2ω2ω2=12kω2I1>I2 and ω2>ω1 so, E2>E1

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Similar Questions

The condition of equilibrium is satisfied when resultant of all forces acting on body vanishes and also no net torque acts on the body. However body can be different types of equilibrium as stable, unstable, neutral or may be having pure rotation when no resultant force acts on the body. Different conditions of equilibrium or rotational motion can be known by different types of energy it possesses. Column I mentions the state of body and column II mentions the type of energy it possesses. Match the correct options in two columns

COLUMN_I COLUMN_II

A) Body in stable equilibrium P) Rotational kinetic energy

B) Body in unstable equilibrium Q) Minimum potential

energy

C) Body in neutral equilibrium R)Maximum potential energy

D) Body in pure rotational motion S) Constant potential energy

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