First slide
Instantaneous velocity
Question

Two boys are standing at the ends A and B of a ground where ,AB - a The boy at B starts running in a direction perpendicular to AB with velocity v1.  The boy at A starts simultaneously with velocity y as shown in figure and catches the other boy in a time t, where t is

Easy
Solution

The velocity of A relative to B is given by
vAB=v2v12
Now, VAB×t=a
or t=avAB=av2v12

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