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Questions  

Two bulbs have filaments of lengths, Emissivities and diameters in the ratio of 2 :1.  If ratio of their powers is 1 : 2 then, ratio of their temperature is

a
1 : 1
b
1 : 2
c
2 : 1
d
1 : 4

detailed solution

Correct option is B

P1P2=σ1A1T14σ2A2T24=σ12πr1l1σ22πr2l2T1T2412=212121T1T24116=T1T24T1T2=12

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