Two capacitors of capacitance C and 2C are charged to potential differences V and 2V , respectively . These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other . The final energy of this configuration is :

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256CV2

92CV2

zero

32CV2

answer is D.

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Detailed Solution

Qfinal = 4CV−CV=3CVCnet = C+2C =3C⇒Ufinal=12Qfinal2Cnet⇒Ufinal=123CV23C⇒Ufinal=32CV2

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