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Q.

Two capacitors of capacitances 3 μF and 6 μF are charged to a potential to 12 v each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

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a

6 V

b

4 V

c

3 V

d

zero

answer is B.

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Detailed Solution

Charge on Ist condenser,Q1=C1V1=3×12=36μCcharge on 2nd condenser,Q2=C2V2=6×12=72μCCommon potential difference of each condenserV=Q2−Q1C1+C2=72−363+6=369=4 volt .
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Two capacitors of capacitances 3 μF and 6 μF are charged to a potential to 12 v each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be