Two capacitors each of capacity C are connected as shown in the circuit across a battery. W1 is the total energy stored in two capacitors when switch is closed. Now the switch S is opened and the two capacitors are immersed in a liquid of dielectric constant K, then the total energy stored in two capacitors is W2. The ratio of W1 and W2 is

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KK+1

2KK2+1

K2K+1

KK2+1

answer is B.

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Detailed Solution

W1=2U0 where U0 is energy in each capacitor when battery is connectedW2=KU0+U0K as one capacitor is disconnected from batteryW1W2=2U0K+1KU0=2KK2+1

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