Questions
Two capacitors 2 F and 4 F are connected in parallel. A third capacitor of 6 F capacity is connected in series. The combination is then connected across a 12 V battery. The voltage across 2 F capacity is
detailed solution
Correct option is B
Resultant capacitance of condensers of capacity 2 μF and 4 μf when connected in parallel C′=2+4=6μFThis is connected in series with a capacitor of capacity 6 μF in series. The resultant capacity C is given by1C=16+16=13 or C=3μFCharge on combinationq=3×10−6×(12)=36×10−6CLet the charge on 2 μF capacitor be q1, thenq12=q−q14 or q1=q3∴ q1=12×10−6CNow potential across 2 μF condenser=q12×10−6=12×10−62×10−6=6VTalk to our academic expert!
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Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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