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Two capacitors 2 μF and 4 μF are connected in parallel. A third capacitor of 6 μF capacity is connected in series. The combination is then connected across a 12 V battery. The voltage across 2 μF capacity is

a
2 V
b
6 V
c
8 V
d
1 V

detailed solution

Correct option is B

Resultant capacitance of condensers of capacity 2 μF and 4 μF when connected in parallel C′=2+4=6μFThis is connected in series with a capacitor of capacity 6 μF in series. The resultant capacity C ls given by 1C=16+16=13  or  C=3μFCharge on combinationq=3×10−6×(12)=36×10−6CLet the charge on 2 μF capacitor be q1 then q12=q−q14  or  q1=q3∴ q1=12×10−6CNow potential across 2 μF condenser=q12×10−6=12×10−62×10−6=6V

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