Questions
Two capacitors with capacitance 2C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors equals:
detailed solution
Correct option is A
q1=2CV, q2=CVNow condenser of capacity C is filled with dielectric K, therefore C2 = KCAs charge is conserved∴ q1+q2=C2+2CV⇒V′=3CV(K+2)C=3VK+2Talk to our academic expert!
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A parallel plate, air filled capacitor has capacitance C. When a dielectric material of dielectric constant 4 is filled so that half of the space between plates is occupied by it, then percentage increase in the capacitance is equal to
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