Two capillaries of same length and radii in the ratio 1 : 2 are connected in series. A liquid flows through them in streamlined condition. If the pressure across the two extreme ends of the combination is 1 m of water, the pressure difference across first capillary is
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a
9.4 m
b
4.9 m
c
0.49 m
d
0.94 m
answer is D.
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Detailed Solution
Given, l1=l2=1, and r1r2=12V=πP1r148ηl=πP2r248ηl⇒P1P2=r2r14=16⇒P1=16P2 Since both tubes are connected in series, hence pressure difference across combination, P=P1+P2⇒1=P1+P116⇒P1=1617=0.94m