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Q.

Two capillaries of same length and radii in the ratio 1 : 2 are connected in series. A liquid flows through them in streamlined condition. If the pressure across the two extreme ends of the combination is 1 m of water, the pressure difference across first capillary is

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a

9.4 m

b

4.9 m

c

0.49 m

d

0.94 m

answer is D.

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Detailed Solution

Given, l1=l2=1, and  r1r2=12V=πP1r148ηl=πP2r248ηl⇒P1P2=r2r14=16⇒P1=16P2 Since both tubes are connected  in series, hence pressure difference across combination, P=P1+P2⇒1=P1+P116⇒P1=1617=0.94m
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