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Q.

Two capillary tubes of the same length but different radii r1 and r2 are fitted in parallel to the bottom of a vessel. The pressure head is P. What should be the radius of a single tube that can replace the two tubes so that the rate of flow is same as before

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a

r1+r2

b

r12+r22

c

r14+r24

d

r14+r241/4

answer is D.

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Detailed Solution

V=V1+V2⇒πPr48ηl=πPr148ηl+πPr248ηl⇒r4=r14+r24∴r=r14+r241/4
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