First slide

Viscosity

Question

Two capillary tubes of same length but different radii r₁ and r₂ are fitted in parallel to the bottom of a vessel. The pressure head is P. What should be the radius of a single tube of same length that can replace the two tubes so that the rate of flow is same as before

Easy

A

$\large r_1^4+r_2^4$
B

$\large \left ( r_1^2+r_2^2 \right )^{1/4}$
C

$\large \left ( r_1^4+r_2^4 \right )^{1/4}$
D

$\large r_1+r_2$

Solution

$\large \frac {\pi Pr^4}{8\eta l}=\frac {\pi P}{8\eta }\left ( \frac {r_1^4}{l_1}+\frac {r_2^4}{l_2} \right )$
Here l₁ = l₂ = l
$\large \therefore r^4=r_1^4+r_2^4\Rightarrow (r_1^4+r_2^4)^{1/4}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App