Two capillary tubes of same length l but radii r1 and r2 are fitted in parallel to the bottom of a vessel. The pressure head is P. What should be the radius r of the single tube, that can replace the two tubes, so that the rate of flow is same as before?
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a
r=r1+r2
b
r=r12+r22
c
r4=r14+r24
d
1r=1r1+1r2
answer is C.
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Detailed Solution
Rate of flow Q=Q1+Q2πPr48ηl=πPr148ηl+πPr248ηl⇒r4=r14+r24