Download the app

Questions  

Two cars are moving on two perpendicular roads towards a crossing with uniform speeds of 72 km/hr and 36 km/hr. If first car blows horn of frequency 280 Hz, then the frequency of horn heard by the driver of second car when line joining the cars make 45° angle with the roads; will be

a
321 Hz
b
298 Hz
c
289 Hz
d
280 Hz

detailed solution

Correct option is B

Here vA=72 km/hr=20m/secvB=36km/hr=10m/secn'=nv+vBcos45ov−vAcos45o⇒n'=280 340+10/2340−20/2=298 Hz

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A source of sound having natural frequency f0 = 1800 Hz is moving uniformly along a line separated from a stationary listener by a distance l = 250 m. The velocity of source is n = 0.80 times the velocity of sound. Find the frequency of sound (in Hz) received by the listener at the moment when the source gets closest to him.


phone icon
whats app icon