First slide

Doppler

Question

Two cars having velocities of 100 and 150 kPh are approaching each other. The frequency of a note emitted by the first as heard by its driver of the other is 1000 Hz. Speed of sound is 330 m/s. The two frequency of sound is

Moderate

A

500 Hz
B

750.6 Hz
C

844.7 Hz
D

900 Hz.

Solution

$n = \frac{v - v_{s}}{v - v_{o}} = \frac{330 - \frac{1000}{36}}{330 + \frac{1500}{36}} \times 1000 = 844.7 Hz$

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